Calculus: Derivatives Problem #2

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Homework Help Overview

The discussion revolves around the calculus problem involving the function y=2x^3+24x-18, specifically focusing on its derivatives and the conditions under which the function is increasing or decreasing.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the conditions for the function to be increasing, particularly questioning the positivity of the first derivative y' and its implications across different intervals.

Discussion Status

There is an ongoing exploration of the relationship between the function's values and its increasing behavior. Some participants have offered clarifications regarding the distinction between the function being negative and the conditions for it to be increasing.

Contextual Notes

Participants are navigating through various interpretations of the problem, including the implications of substituting specific values into the function and the relevance of the derivative's sign in determining increasing or decreasing intervals.

Hothot330
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[SOLVED] Calculus: Derivatives Problem #2

Homework Statement


The graph of y=2x^3+24x-18 is


Homework Equations


y '=6x^2+24
y ''=12x

The Attempt at a Solution


The answer to this is "increasing for all values of x"
But I want to know why...if substituting -1 for x will make the problem a negative.
 
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What's the question? If you want to find where y is increasing it's where is y' positive. You don't think y' is positive for all x?
 
because when you plug in -1 for y=2x^3+24x-18 the end result is a negative not positive.

The other choices to the questions are:
b.decreasing for all values of x
c.only increasing for values of x on the interval (-infinity,-2)U(2,+infinity)
d.only increasing for values of x on the interval (-2,2)
e. only decrasing for values of x on the interval (-infinity,-2)
 
NVM, TOTAL IDIOT HERE... I know what you're saying now. Thanks.
 
The question isn't where y is negative, it's where y in increasing. y can be increasing even if it's negative.
 

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