Calorimeter Homework: Clock Period & Temperature Change

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The discussion revolves around a homework problem involving a clock with a pendulum that is designed to operate accurately at 20.0°C but is instead used at −80.0°C. It addresses whether the clock will run fast or slow due to temperature effects on the pendulum's period. The coefficient of linear expansion for aluminum is provided to help determine changes in the pendulum's length and, consequently, its period. Participants suggest using the equations for heat transfer and linear expansion to solve the problem, indicating the need to calculate the pendulum's length. The conversation emphasizes understanding the impact of temperature on pendulum motion to find the clock's time deviation.
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Homework Statement



A clock is designed with a simple pendulum, consisting of a mass at the end of an aluminum rod, whose period is supposed to be equal to one second. The clock is designed to keep accurate time at 20.0°C, but is operated at a constant temperature of −80.0°C. (a) Will the clock run fast or slow? Explain. (b) How many periods will the pendulum go through before the clock is off by 1.00 s? (The coefficient of linear expansion of aluminum is 2.31×10−5 1/C°.)

Homework Equations


Q = cmΔT
Qw + Qo = 0
ΔL = LiαΔT



The Attempt at a Solution


i tried several time using those equation above, but it didnot give the right answer, please help or give me hints.thank
 
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