Why ignore heat from condensed steam cooling in calorimetry

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ritwik06
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Homework Statement


What mass of steam at 100 degree celsius must be passed into 5.4 kg of water at 30 degree celsius to raise temperature of water to 80 degree celsius?


Homework Equations



C(water)=4.2 J/(g C)
L(steam)=2268 J/g

The Attempt at a Solution


Assuming no heat loss,
Heat gained by water=Heat given by steam by changing to water+ heat released by water so formed to fall from 100 degree to 80 degree

5.4*50*4200=m*2268000+m*4200*20
1134000=m(2352000)
m=0.482142857 Kg

My book gives me the answer as 0.5 Kg. It neglects the heat given by water formed from steam, it seems. why?
 
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ritwik06 said:

Homework Statement


It neglects the heat given by water formed from steam, it seems. why?

What does this mean?
 
Amith2006 said:
What does this mean?

I mean that the water formed from condensation of steam will also provide heat to the water at 30 degree, isn't it?
 
ritwik06 said:
I mean that the water formed from condensation of steam will also provide heat to the water at 30 degree, isn't it?

Yes, youre right... but does all of the steam need to be condensed? If it doesnt, then only steam will give the heat first because it has more energy...
 
chaoseverlasting said:
Yes, youre right... but does all of the steam need to be condensed? If it doesnt, then only steam will give the heat first because it has more energy...

What do you think that the question wants me to do?
 
ritwik06 said:
I mean that the water formed from condensation of steam will also provide heat to the water at 30 degree, isn't it?

That is latent heat which has already been included in your solution.
 
Amith2006 said:
That is latent heat which has already been included in your solution.

No that isn't laten heat. Somebody help!