Can a defective DRC on a heat pump cause the fan motor to go bad?

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A defective Dual Run Capacitor (DRC) can indeed cause a fan motor to fail, particularly in a PSC motor setup. Insufficient capacitance from the DRC can prevent the motor from starting, leading to excessive current draw that overheats and damages the motor's windings. The discussion highlights the importance of checking both the DRC and the fan motor's resistance readings to diagnose issues accurately. It is noted that while some motors have thermal overload protection, this may not always prevent failure if the motor cycles too frequently. Ultimately, replacing the defective components is necessary to restore functionality.
  • #31
Sneaky!
C= Capacitance
A= Amps
V= Volts
k= 2652

C= kA / V
C= k⋅(A/V) - - - (V/A)= R but it's a capacitor so (V/A)= Xc (capacitive reactance)
but it's not (V/A), it is (A/V) . so (A/V)≡ 1/Xc

C= k⋅(1/Xc)
Now (1/2652) = 0.000377
The formula @jim hardy gave for Xc has 377 in the denominator. Your formula has moved the reciprocal of 377 to the numerator, which has the same mathematical effect. The factor of 1 million difference between the two is because your formula gives the result directly in microfarads, whereas jims formula answers in farads.

Nice shortcut.

I see @Averagesupernova types faster than I do.

Cheers,
Tom
 
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  • #32
Aha !

2652 X 2π X 60 = almost a million

copying from Windows calculator
upload_2018-12-19_21-51-33.png
X 2π X 60 = exactly a million

to get from farads to microfarads

If i learn something every day i might know something someday !

old jim
 

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  • #33
fourthindiana said:
Capacitance (MFD)= (Start winding amps X 2652)/Volts from start to run

Tom.G said:
Nice shortcut.

Indeed !
So nice i just had to figure out how a way that i can remember it.
With my scattered brain i'll roll digits

so i wound up back at conductance, the old Mhos trick

##Ohms = \frac{1}{2πfC}##
so ##Mhos = 2πfC##
which means ##C = Mhos X \frac{1}{2πf}##
but that's in Farads
in Microfarads it's ##C = Mhos X \frac{1,000,000}{2πf}##

and since Mhos = Amps/Volts

##C= \frac{Amps}{Volts} X \frac{1.000.000}{2πf}##

and at 60hz, ##\frac{1.000.000}{2πf} = 2652.58...##

hence your ##C = \frac{Amps}{Volts} X 2652## , good to four digits which is probably better than the ammeter.

it's easier for me to just remember C = Mhos/2πf
and that's what i'll do

Thanks, Guys,
for showing this old dog a new trick !

old jim
 
Last edited:
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  • #34
jim hardy said:
Thanks, Guys,
for showing this old dog a new trick !

old jim

You're welcome.
 

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