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Can all limits questions be solved algebraically?

  1. Jan 12, 2013 #1
    [tex]
    \lim_{n\rightarrow 0} {\frac{√(x+4) - 2}{x}}
    [/tex]


    The answer is supposed to be 1/4. When I work it this way:

    (√(x+4) - 2]/x )(√(x+4) + 2]/√(x+4) +2]

    and then put in 0 I get 0..
     
  2. jcsd
  3. Jan 12, 2013 #2
    Oh sorry I A FLIPPING IDIOT!!!!!!!!!!!!!!!!!!! .............. I AM SO STUPID my gosh, all I had to do was divide it by x........... and I would 1 and 4 as the numerator and denominator respectively.
     
  4. Jan 12, 2013 #3

    haruspex

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    Bracketing is a bit off. I guess you mean (√(x+4) - 2]/x )(√(x+4) + 2)/(√(x+4) +2)
    I don't. Please post your working.
     
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