- #1
lionely
- 576
- 2
[tex]
\lim_{n\rightarrow 0} {\frac{√(x+4) - 2}{x}}
[/tex]The answer is supposed to be 1/4. When I work it this way:
(√(x+4) - 2]/x )(√(x+4) + 2]/√(x+4) +2]
and then put in 0 I get 0..
\lim_{n\rightarrow 0} {\frac{√(x+4) - 2}{x}}
[/tex]The answer is supposed to be 1/4. When I work it this way:
(√(x+4) - 2]/x )(√(x+4) + 2]/√(x+4) +2]
and then put in 0 I get 0..