- #1

lionely

- 576

- 2

\lim_{n\rightarrow 0} {\frac{√(x+4) - 2}{x}}

[/tex]The answer is supposed to be 1/4. When I work it this way:

(√(x+4) - 2]/x )(√(x+4) + 2]/√(x+4) +2]

and then put in 0 I get 0..