Can Anyone Solve the Integral of 1/ln(x)?

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Homework Help Overview

The discussion revolves around the integration of the function f(x) = 1/ln(x). Participants are exploring methods to solve this integral, which appears to be more complex than initially thought.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts substitution with t = ln(x) but encounters difficulties in progressing with the integral. Others mention the result from Mathematica, suggesting the integral may not have a closed form. There is also a reference to a series solution from an integral table.

Discussion Status

The discussion is ongoing, with participants sharing different insights and approaches. Some guidance has been offered regarding the potential complexity of the integral, but there is no explicit consensus on a method or solution yet.

Contextual Notes

Participants are referencing external threads and integral tables, indicating that the problem may have roots in broader mathematical contexts. The mention of a series solution suggests constraints in finding a straightforward answer.

Dell
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how would you integrate the following, seemingly simple, function.

f(x)=1/ln(x)

what i tried to do was substitution
t=ln(x)
x=et
dt=dx/x

but from here i get to an integral of [tex]\int[/tex]((et)/(t))dt, no idea how to continue, tried integration in prts but keep going in cirlces, can anyone see how to do this?
 
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When I plug it into Mathematica, I get
LogIntegral[x]
as the answer.

So I think there is no closed form.
 
Dell said:
[tex]\int[/tex]((et)/(t))dt, no idea how to continue, tried integration in prts but keep going in cirlces, can anyone see how to do this?

My integral table has this, but it is a series solution.

[tex]=ln(t)+t+{{t^2}\over{(2)\;2!}}+{{t^3}\over{(3)\;3!}} + ...[/tex]
 

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