Can conversion of medium occur in sound?

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Sound waves produced by a vibrating object in air can interact with a solid object in various ways, including reflection, absorption, and propagation within the solid. The extent of these interactions depends on the material properties of the solid and the frequency of the sound. Generally, part of the sound wave will be reflected while another part will propagate into the solid, experiencing attenuation. The acoustic impedance of the materials involved plays a crucial role, with significant impedance mismatches leading to stronger reflections. Understanding these principles is essential for applications like soundproofing and acoustic engineering.
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If vibrating object produces sound in air and there's a solid object in front of it after some distance, will those sound waves(which were propagating in air before) start propagating within that same solid object or reflected or absorbed or etc.
Please explain also.
Thanks.
 
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hasankamal007 said:
If vibrating object produces sound in air and there's a solid object in front of it after some distance, will those sound waves(which were propagating in air before) start propagating within that same solid object or reflected or absorbed or etc.
Please explain also.
Thanks.
It depends on the nature of the material (don't ask me further - you need to discuss this with a sound engineer). Soundproof rooms use material which absorbs the sound. Other material may reflect some and transmit some.
 
hasankamal007 said:
If vibrating object produces sound in air and there's a solid object in front of it after some distance, will those sound waves(which were propagating in air before) start propagating within that same solid object or reflected or absorbed or etc.
All these things will happen, in general. Part of the wave will be reflected, part will propagate in the solid, being attenuated in the process. The relative importance of these phenomena depends of the solid and the sound frequency.
A good parameter to look at is the acoustic impedance of the medium.
A large impedance mismatch at the interface will result in strong reflection.
The acoustic impedance of the medium is Z=d*v where d is density and v is the speed of sound in the medium.
 
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