Hmm, you are describing equipotential lines.
I usually think of electric field lines as pointing along the gradient of the potential, i.e. going from positive potential to negative in the same way that magnetic field lines go from north to south.
In any case, this type of field line cannot cross either. Think of the field line indicating the direction of the slope on a hill. That can only point in one direction. When you come to a saddle point (the pass between two hills), then the top is flat, i.e. no gradient, no field line. Move off the top a little bit and the slope starts to become steeper, but it will point in only one direction.
This situation will occur with a quadrupole arrangement. Take 2 positive and 2 negative charges (+Q and -Q).
Put +Q at (A ,0) and (-A, 0).
Put -Q at (0, A) and (0, -A).
Then at (0,0) there is no potential gradient, hence no electric field.
By symmetry you expect field lines to run along the x and y axes, and they seem to cross at (0,0). But if you look closely the do not reach (0,0) because there is no field, hence no field line.
As DaveC pointed out, field lines are artificial constructs to help visualize invisible electric and magnetic fields. Just drawing lines gives no impression of the field strength, so this representation is incomplete. Don't try to overstretch this means of visualizatin by constructing pathological cases.
Equipotential lines are a bit better for this as the density of lines gives an idea of the gradient (slope).