Can Induction Prove the Equality of Cubic and Square Sums?

AI Thread Summary
The discussion centers on proving by induction that the sum of cubes of the first n integers equals the square of the sum of the first n integers. The initial step confirms the base case for N=1. The user attempts to apply the induction hypothesis for k and then for k+1, but encounters a discrepancy between the left-hand side (LHS) and right-hand side (RHS) of the equation, specifically regarding the presence of k^3 and k^2 terms. The user seeks clarification on whether the two sides are indeed supposed to be equal and hints at a potential pattern related to the formula for the sum of integers. The inquiry emphasizes the need for assistance in identifying the error in their induction approach.
Trentonx
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Homework Statement



Prove by induction \sum\limits_{i=0}^n i^3 = (\sum\limits_{i=0}^N i)^2

Homework Equations


The Attempt at a Solution



So I used N=1 and found that indeed, 1^3 = (1)^2

Then I assumed it was valid up to some limit k, and tried to find it for k+1
(1^3+2^3+...+k^3+(k+1)^3)=(1+2+...+k+k+1)^2
(9+...+2k^3+3k^2+1)=(4+...+2k)^2
Right here I can see a problem, since the RHS will have a k^2 term, and the LHS will have k^3. Where did I go wrong? Are they supposed to be equal?
Thanks for any help.
 
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Do you know the expression Sum of i 1 to n is n*(n+1)/2 ? There's a pattern there. When you sqaure it, maybe you will find a k^3
 
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