Can Linear Expansion Formula Be Used for a Heated Brass Spring?

AI Thread Summary
The discussion centers on the application of the linear expansion formula to calculate the compressional force needed to return a heated brass spring to its original length. The user calculates the change in length using the coefficient of linear expansion for brass, resulting in a change of 3.89 x 10^-4 m. They then apply this change to the spring constant formula, yielding a compressional force of 5.07 N. The user expresses confidence in their approach, suggesting that it is a straightforward solution. Overall, the method of using linear expansion to determine the force on the spring is deemed appropriate.
rsyodoom2005
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1. A brass spring has an unstrained length of .18m and a spring constant of 1.3 E4 N/m. THe temperature increases from 21 cel to 135 cel. what is the magnitude of the compressional force that must be applied to the heated spring to bring it back to its original lenght!?



2. Linear expansion; Change of lenght= constant *lenght * change of temp
F= K Change of lenght




the thing i am concern is with Linear expansion formula can i use this fromula for the spring?! I figure out my change of length first my multyplying my coeficcient of brass
(9*10^-6)* .18m * 135-21 to get a result of 3.89*10^-4

Then i clicked it on to the spring constan formula using F= 1.3*10^4 * the distance of 3.89*10^-4 to myforce of 5.07N... is this a right approach?
 
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Must be correct.I don't think that this question needs more complicated solution.
 

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