Can Nonlinear Congruences Be Solved? A Case Study with a Prime Modulus

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Homework Help Overview

The problem involves finding an integer solution to the congruence equation 13x ≡ 13 (mod 50032), with the condition that x > 1. The context includes the use of prime modulus, specifically noting that 5003 is prime.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various techniques, including Fermat's Little Theorem and Euler's theorem, to approach the problem. There is uncertainty about how to manipulate the results of these theorems to find the desired congruence.

Discussion Status

The discussion is ongoing, with participants sharing insights and techniques. Some guidance has been offered regarding the application of theorems, but there is no clear consensus on the next steps or a solution yet.

Contextual Notes

Participants note the challenge of the problem due to the lack of examples in their reference materials and the original poster's uncertainty about the appropriate equations to use.

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Homework Statement



Find an integer x that is a solution (only need one solution, not all solutions). If no solution exists, prove that no solution can exist.

13x = 13 mod 50032 , with x > 1. Note that 5003 is prime.

Here, = means "congruent to"

Homework Equations



Not sure. I can solve linear congruences without too much trouble, but I haven't seen a congruence of this form before, and the book that I'm using is pretty low on good examples.

The Attempt at a Solution



I don't have one. Looking for a bump in the right direction.
 
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I spent a lot of time last night trying a bunch of different techniques on your problem and couldn't get much of anywhere. But since no one else has responded to it yet I will give you what little I have, which is just Fermat's Little Theorem:

13^5003 = 13 mod 5003. But from here I don't know where to go.
 
I can use Euler's theorem since 13 and 50032 are coprime.

However, I then end up with: 13phi(50032) = 1 mod 50032. How can I manipulate this so that I have 13 mod 50032 instead of 1 mod 50032?
 
Can't you just multiply both sides by 13?
 
Sigh ... yes. Yes I can. I think it's time for a break, I've been staring at this for too long and I'm starting to forget about basic math.

Thanks for the wake up call!
 

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