Can Physics Principles Clarify Ground Resistance in a Piledriver Problem?

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The discussion focuses on solving a physics problem involving a piledriver hammer and its interaction with a pile. The user successfully calculated the striking speed of the hammer as 9.905 m/s and the time of fall as 1 second. They then attempted to find the average resistance force when the hammer strikes the pile, calculating an acceleration of -654.06 m/s² and a resistance force of -349.733 kN. However, there is confusion regarding the application of conservation laws, particularly in determining the initial speed of the combined pile and hammer after the collision. Participants suggest incorporating conservation of momentum and revisiting the equations to clarify the process.
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hi there, i was wondering if anybody could help me with some problems i am having great difficulty getting my head around at the minute, any help would be greatly appreciated.


Homework Statement





The first question is:
A piledriver hammer of mass 150kg falls freely through a distance of 5m to strike a pile of mass 400kg and drives 0.075m into the ground. the hammer does not rebound when driving the pile. Determine the average resistance of the ground.

The second question is linked to the first and is: Compare and contrast the use of D'Alembert's principle with the principle of conservation of energy when solving the problem given above.



so far i have used linear equations to work out the striking speed of the hammer. using:
s = 5m
a = 9.81m/s (gravity)
u = 0m/s (initial velocity)

i worked out v in the equation v(squared) = u(squared) + 2as. this came to 9.905m/s (striking speed)

i then put this value into v = u + at. and found t = 1second.


my next step was to find the resistance force when the hammer has struck the object and now they are moving together.

u = 9.905m/s (striking speed)
v = 0m/s (stops dead)
s = 0.075m (distance it goes into the ground)

i found a using v(squared) = u(squared) + 2as. this came to -654.06m/s

and t using v = u + at. this came to 0.015seconds.

i then used the resistance force equation F=ma. 550 x -654.06 = -349.733kN


this was quite straight forward after a few steps back to think about it, but I am not sure if i have done the right process.

Homework Equations


v = u+at
V(squared) = U(squared) + 2as
F = ma
I = mv - mu
I = Ft


if this is correct, then the main problem for me is to work out the next stage of the question which is using the principle of conservation of energy. It has me really stumped because we don't have an example to follow that is similar, or anything even closely linked to it that we may use.

any help would be greatly appreciated, even just to clarify that my first question is correct.

thankyou all in advance
 
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Hi Manners, Welcome to PF.

Manners said:
hi there, i was wondering if anybody could help me with some problems i am having great difficulty getting my head around at the minute, any help would be greatly appreciated.


Homework Statement





The first question is:
A piledriver hammer of mass 150kg falls freely through a distance of 5m to strike a pile of mass 400kg and drives 0.075m into the ground. the hammer does not rebound when driving the pile. Determine the average resistance of the ground.

The second question is linked to the first and is: Compare and contrast the use of D'Alembert's principle with the principle of conservation of energy when solving the problem given above.



so far i have used linear equations to work out the striking speed of the hammer. using:
s = 5m
a = 9.81m/s (gravity)
u = 0m/s (initial velocity)

i worked out v in the equation v(squared) = u(squared) + 2as. this came to 9.905m/s (striking speed)
Okay, striking speed looks fine.
i then put this value into v = u + at. and found t = 1second.


my next step was to find the resistance force when the hammer has struck the object and now they are moving together.

u = 9.905m/s (striking speed)
v = 0m/s (stops dead)
s = 0.075m (distance it goes into the ground)

i found a using v(squared) = u(squared) + 2as. this came to -654.06m/s

and t using v = u + at. this came to 0.015seconds.

i then used the resistance force equation F=ma. 550 x -654.06 = -349.733kN
Okay, bit of a problem with that last part. When the pile driver slams into the pile, what you have in essence is a perfectly inelastic collision. The pile+driver is not going start with the same speed as the driver alone before the collision. What conservation law can you apply to find out what the initial speed of the pile+driver?
 


To be honest mate we havnt included a lot of other laws to the problem. It's only a Btec ND question so we are including those equations above.
The only other thing I can think of doing is using the linear equations again to work backwards through it and find the speed of the pile, as it starts from 0 and I already have the distance.
 


Manners said:
To be honest mate we havnt included a lot of other laws to the problem. It's only a Btec ND question so we are including those equations above.
The only other thing I can think of doing is using the linear equations again to work backwards through it and find the speed of the pile, as it starts from 0 and I already have the distance.

That might be problematical since you aren't given the length of time that the pile is moving.

I suggest that you add conservation of momentum to the repertoire of equations :wink:
 
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