- #1
Kara386
- 208
- 2
I have the equation
##qV = E_g + T[kln(\frac{I}{A}) - (3 + \frac{\gamma}{2})kln(T)]##
So if I plot ##qV## against ##T## that'll be a straight line with the y-intercept being ##E_g##. But then my lab manual says a more precise value of ##E_g## can be found by plotting the corrected value
##qV_c = qV + (3 + \frac{\gamma}{2})kTln(T)##
So does that mean if I want to plot ##qV_c## against ##T##, which I think is what's being asked, then I should plot
##qV_c = E_g + kTln(\frac{I}{A})##
And I'll get my more accurate ##E_g##?
##qV = E_g + T[kln(\frac{I}{A}) - (3 + \frac{\gamma}{2})kln(T)]##
So if I plot ##qV## against ##T## that'll be a straight line with the y-intercept being ##E_g##. But then my lab manual says a more precise value of ##E_g## can be found by plotting the corrected value
##qV_c = qV + (3 + \frac{\gamma}{2})kTln(T)##
So does that mean if I want to plot ##qV_c## against ##T##, which I think is what's being asked, then I should plot
##qV_c = E_g + kTln(\frac{I}{A})##
And I'll get my more accurate ##E_g##?