Can pressure cause gravity in a box of light?

  • Thread starter Thread starter Elroch
  • Start date Start date
  • Tags Tags
    Box Light
Elroch
Messages
138
Reaction score
12
Imagine a perfectly reflecting box with a homogenous distribution of photons within it with total energy E (not entirely sure how close to possible this is, but don't worry about that).

I would have thought this box's gravitational field would be very much like the combination of the the box's effect and a mass E/c^2 inside the box. Intuitively, it is quite easy to see the light provides a little extra inertia (because of the effect of motion of the box on the reflections of photons on the walls - the pressure of the photons on the walls is unbalanced if the box is accelerated. Hopefully the arithmetic means that this inertia is the same as there would be from a mass of E/c^2 regardless of the box's dimensions!

In the Einstein field equations, if the box is in an inertial frame I would expect the light within the box to have no direct effect, because the net momentum flux is zero in any direction. But perhaps the reflection of the photons off the walls does all the work - with momentum being continually supplied to the photons from the box at every surface? Is this the non-zero contribution to the Einstein field equations?
 
Last edited:
Physics news on Phys.org
There's an exact solution in GR for a photon star. This sheds a lot of light on the question of the "box of light", all you need to do is to add an enclosure to this solution and you've got the complete metric of a box of light.

While the general solution of a photon star in GR requires numerical analysis, there's an "easy case" that you can write down the metric of.

See the following old threads:

https://www.physicsforums.com/showpost.php?p=3578660&postcount=104
https://www.physicsforums.com/showpost.php?p=3580696&postcount=111

The first gives the URL of a paper with the photon star metric.

The second thread discusses how to "enclose" the photon gas star in a shell of exotic matter with zero density and finite tension.

Because the star (and the box of light) is static, you can useful use the notion of the Komar mass to calculate the gravitational field. If you don't have significant time dilation this is just the integral of (rho+3P). The important thing to note here is that pressure causes gravity, and there is a lot of pressure in a box of light that has any significant energy content.

You mentioned momentum flux, but you didn't take into account pressure, which turns out to be important.

Another lesson to be learned - you can define other sorts of mass for this system, with different distributions. However, the Komar mass is the only one that directly relates to the measured gravitational acceleration of a test object.

The Komar mass distribution in the interior of the star is different from the special relativistic mass distribution, and you'll get incorrect results by a factor of about 2:1 if you try to estimate the gravity by E/c^2 and Newton's law.

Outside the shell enclosing the star, E/c^2 provides a good approximation, if you define E properly.
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Does the speed of light change in a gravitational field depending on whether the direction of travel is parallel to the field, or perpendicular to the field? And is it the same in both directions at each orientation? This question could be answered experimentally to some degree of accuracy. Experiment design: Place two identical clocks A and B on the circumference of a wheel at opposite ends of the diameter of length L. The wheel is positioned upright, i.e., perpendicular to the ground...
According to the General Theory of Relativity, time does not pass on a black hole, which means that processes they don't work either. As the object becomes heavier, the speed of matter falling on it for an observer on Earth will first increase, and then slow down, due to the effect of time dilation. And then it will stop altogether. As a result, we will not get a black hole, since the critical mass will not be reached. Although the object will continue to attract matter, it will not be a...
Back
Top