Can Proportional Variation be Deduced Algebraically from Given Equations?

dx
Homework Helper
Messages
2,143
Reaction score
52
Consider the following situation :

There are three variables A, B and C. (and i,j,k are constants )
Keeping C constant, and varying the other two, you find that

A = kB ------(1)

Now, Keeping B constant, and varying the other two, you find that

A = iC ------(2)

I know that it follows from these two observations that

A = jBC

But I am not sure how we can algebraically deduce this from the equations (1) and (2).

We get A^2 = ikBC

Presumably, ik = \sqrt{j}BC
But how do we deduce this?
 
Mathematics news on Phys.org
You have

A = k(C) \times B = i(B) \times C

where k and i are functions of C and B, respectively. If B and C are independent variables then the only way k(C)B and i(B)C can be equal is if k is proportional to C and i is proportional to B. Therefore, A = jBC.
 
Thanks for the help.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top