Professor Susskind said that the expectation value of all three sigma operators acting on a singlet pair are zero. Does that mean that a singlet pair can not be prepared in a preferred direction?
I assume you are talking about the singlet (total L = 0) state of two spin-1/2 particles? This state has no preferred direction: it is spherically symmetric (this is true of any L = 0 state, no matter how complicated).
This causes no particular trouble in preparing a singlet state of two spin-1/2 particles. For example, the ground state of hydrogen (which consists of two spin-1/2 particles, the proton and the neutron) is the spin singlet state, so hydrogen atoms naturally fall into this state. If the singlet state were actually an excited state, though, we could still easily prepare hydrogen atoms in the singlet state by exciting them to the appropriate energy level with e laser.
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles.
Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated...
Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/
by @RUTA
I am reading WHAT IS A QUANTUM FIELD THEORY?" A First Introduction for Mathematicians.
The author states (2.4 Finite versus Continuous Models) that the use of continuity causes the infinities in QFT:
'Mathematicians are trained to think of physical space as R3. But our continuous model of
physical space as R3 is of course an idealization, both at the scale of the very large and
at the scale of the very small. This idealization has proved to be very powerful, but in the
case of Quantum...
The lesser Green's function is defined as:
$$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state.
$$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$
First consider the case t <t'
Define,
$$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$
$$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$
$$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$
##\ket{\alpha}##...