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viciousp
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Can some one explain why I am getting this wrong[SOLVED]
Evaluate
\int ln(x+x^{2}) dx
I integrated by parts to get down to xln(x+x^{2})-\int \frac{(2x-1)}{x+1} I set u=1+x which led to du=1 dx and x=u-1 after so evaluation I got down to -(\int 2 du -\int \frac{1}{u} du) and after more substitution and evaluation I got down to xln(x+x^{2})+ln\left|1+x \right|-2-2x +C, but my book says that I should have only got -2x and not that extra -2
Homework Statement
Evaluate
\int ln(x+x^{2}) dx
Homework Equations
The Attempt at a Solution
I integrated by parts to get down to xln(x+x^{2})-\int \frac{(2x-1)}{x+1} I set u=1+x which led to du=1 dx and x=u-1 after so evaluation I got down to -(\int 2 du -\int \frac{1}{u} du) and after more substitution and evaluation I got down to xln(x+x^{2})+ln\left|1+x \right|-2-2x +C, but my book says that I should have only got -2x and not that extra -2
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