So If I understand you correctly, this is how I would go about answering the question.
Suppose that a 1 foot flexible piece of wire is stretched between the points (0,0) and (1,0). The tension in the wire is 10 Ib and the weight of the wire is 0.032 Ib. The parameter "a" in the wave equation is defined as a2 = Tension/density; therefore since
mg = 0.032 Ib and δ(linear mass density) = m/L, a2 = (10 Ib) (32 ft/s2)(1 ft)/(0.032 Ib) = 104 (ft/s)2
The wave equation then becomes ytt(x,t) = 104 yxx(x,t)
At t = 0 the string lies completely on the x-axis but has a velocity of 1 ft/s in the positive y - direction. The wire is under no external forces.
Since the wire is being stretched between the endpoints, that implies that the endpoints are fixed, therefore
y(0,t) = y(L,t) = 0 for t ≥ 0
it was said that the wire lies completely on the x-axis at t = 0, therefore
y(x,0) = 0 for 0 ≤ x ≤ 1
Since the velocity of the wire at t = 0 was 1 ft/s
yt(x,0) = 1 for 0 < x < 1
So in short, the physical process described above can be summarized in the following way
ytt(x,t) = 104 yxx(x,t) for 0 < x < 1 for t > 0
y(0,t) = y(L,t) = 0 for t ≥ 0
y(x,0) = 0 for 0 ≤ x ≤ 1
yt(x,0) = 1 for 0 < x < 1