Can someone correct my questions and help me please.

[54088]

The line y = x + 2 intersects the curve 4y + 3x^2 = 7 in two places.

a) Find the coordinates of the two points of intersections.

>Sub. y = x + 2 to 4y + 3x^2 = 7
>4(x+2) + 3x^2 = 7
>4x + 8 + 3x^2 -7 = 0
>3x^2 + 4x -1 = 0
>x = -1 and - 1/3
>y = x + 2
>so y = 1 or 5/3

The straight line y = f(x) has gradient 3 and intersects the curve 4y + 3x^2 = 7 at one point only.

b) Find f(x).

>?

c) Hence find the coordinates of the point of intersection between y = f(x) and 4y + 3x^2 =7

>?

:(

 

[mensa]

to question b)
we know that y = f(x) has gradient 3, so y=3x+m, and 4y+3x^2=7
>4(3x+m)+3x^2=7
>3x^2+12x+4m-7=0
at one point only, so the equation above has only one solution, Δ=0
>m=17/4

q c) is easy ^.^

 

[54088]

Thankyou Very Much! ^^"

 

[liltrina01]

The line y = x + 2 intersects the curve 4y + 3x^2 = 7 in two places.

a) Find the coordinates of the two points of intersections.

>Sub. y = x + 2 to 4y + 3x^2 = 7
>4(x+2) + 3x^2 = 7
>4x + 8 + 3x^2 -7 = 0
>3x^2 + 4x -1 = 0
>x = -1 and - 1/3
>y = x + 2
>so y = 1 or 5/3

The straight line y = f(x) has gradient 3 and intersects the curve 4y + 3x^2 = 7 at one point only.

b) Find f(x).

>?

c) Hence find the coordinates of the point of intersection between y = f(x) and 4y + 3x^2 =7

>?

:(

i think that alright you aint to old or to young to learn more

 

[berkeman]

to question b)
we know that y = f(x) has gradient 3, so y=3x+m, and 4y+3x^2=7
>4(3x+m)+3x^2=7
>3x^2+12x+4m-7=0
at one point only, so the equation above has only one solution, Δ=0
>m=17/4

q c) is easy ^.^

Do NOT do the OP's work for them. They are required to do their own homework here at the PF.