Can someone explain this to me

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Let speed be s

s^2 = 4^2 + 9^2

s^2 = 377

s = 19.4 mph

Ө = Tan^(-1) [ 19/4 ] = 78.1°

3 figure bearing is thus 180 ° - 78.1 ° = 101.9 °

109.1 ° = N 11.9 ° W

Why 109.1 ° = N 11.9 ° W.
 
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You have a typo at the end of your post.

xpack said:
Let speed be s

s^2 = 4^2 + 9^2

s^2 = 377

s = 19.4 mph

Ө = Tan^(-1) [ 19/4 ] = 78.1°

3 figure bearing is thus 180 ° - 78.1 ° = 101.9 °

109.1 ° = N 11.9 ° W.

Why 109.1 ° = N 11.9 ° W.

It isn't: the result is 101.9^\circ, not 109.1^\circ. With N at 90^\circ, the result is 11.9^\circ west of that, hence the N 11.9^\circ W.
 
Oh man! So stupid of me. Thanks!
 
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