ainster31
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Homework Statement
Homework Equations
The Attempt at a Solution
$$\int _{ 0 }^{ 2\pi }{ xdx } \\ =-\int _{ 0 }^{ 2\pi }{ sintcostdt } \\ =0$$
It feels wrong.
The discussion centers on the evaluation of the line integral $$\int _{ 0 }^{ 2\pi }{ xdx }$$, where the variable x is defined as $$x = \cos(t)$$ and $$dx = -\sin(t) dt$$. The integral evaluates to zero due to the periodic nature of sine and cosine functions over the interval from 0 to 2π, resulting in the cancellation of positive and negative areas. It is clarified that this integral represents the integration of x around a circle, not the integral of x itself over the same interval, which would yield a different result.
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