Can someone me understand this lesson? I tried, but I just can't get it

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The discussion focuses on understanding vector operations and their graphical representation. Users seek clarity on calculating the vector SP given vectors PQ, RQ, and RS. A suggestion is made to visualize the vectors by drawing right triangles to represent their components, aiding in comprehension. The relationship between vectors is emphasized, particularly how to derive SP using the other vectors. A diagram is recommended for better tracking of the points and vectors involved.
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The lesson can be found at www.sol-ah.tumblr.com

And also some help with this question please ~

If Vector PQ = [-1 , 4]
Vector RQ = [2 , 1]
Vector RS = [-3 , 2]
what is Vector SP ?


Thanks!
 
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Is it possible to get a more zoomed in version of the lesson?

A diagram would be best to help you keep track of everything.

Start with a point P, and draw a vector to the point Q. To know which direction you need to roughly point towards, you can get an idea of this by looking at the components of the vector. PQ = [-1,4] which means that from P it heads -1 units in the x direction and 4 units in the y direction, so the vector is pointing in the NW direction and more North than West. Now keep a label of the x and y components of this vector by drawing a right triangle with the hypotenuse being the vector.

For the vector RQ notice that it is equal to -QR, which means you can instead draw QR = [-2,-1]. It's not necessary to do this, and if you can figure out where the point R should be located roughly in order for the vector to point to Q, then I'd say just skip it altogether.

Now do this for the rest of the vectors. Finally, draw the vector SP. Can you determine what its components are?
 


Dosirak said:
If Vector PQ = [-1 , 4]
Vector RQ = [2 , 1]
Vector RS = [-3 , 2]
what is Vector SP ?

You can write \vec{PQ} = \vec{OQ} - \vec{OP} = -\hat{i} + 4\hat{j}

same for the other two ...

And you need \vec{SP} = \vec{OP} - \vec{OS}

now play a little with equations to get the answer ...
 
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