Can someone please explain this problem to me

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The discussion centers on understanding the free body diagram (FBD) for a problem involving slip-joint pliers. The key point is that when analyzing the forces, the 30 lb upward force is not included in the FBD because it is considered internal when isolating one part of the pliers. The force exerted by the circular component of the pliers is normal to the contact point and can be resolved into horizontal and vertical components, which are shown as acting in the +x and -y directions. Newton's third law is referenced to explain how the forces interact, emphasizing that the handles must be squeezed together to create the necessary motion. Overall, the discussion clarifies the relationship between the forces acting on the pliers and the importance of proper FBD representation.
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Homework Statement


https://docs.google.com/a/rams.colo...&sig=AHIEtbQGcbZbLABawi6f0FTNFXdQt_G2CA&pli=1


That's the link to the problem. It's problem 4/67. I don't understand why in the FBD in my solution manual they took away the 30lb force pointing up and have the force on the circle thing pointing in the +x and -y direction. Can someone explain this to me please? Thanks.
 
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doubled said:

Homework Statement


https://docs.google.com/a/rams.colo...&sig=AHIEtbQGcbZbLABawi6f0FTNFXdQt_G2CA&pli=1


That's the link to the problem. It's problem 4/67. I don't understand why in the FBD in my solution manual they took away the 30lb force pointing up and have the force on the circle thing pointing in the +x and -y direction. Can someone explain this to me please? Thanks.
since the force on the pin is internal, you have to 'take apart' the pliers in a 'free body diagram' of one of the 2 pieces, in order to solve for the internal forces. When you do this, the other 30 lb force is not in the picture. The force of the circle thing on that part of the pliers is perpendicular (normal) to the contact point, and can be broken into its horizontal and vertical components.
 
Oh thanks a lot. So if we look at the top part wouldn't the 30lb force pointing down be applying a force on the circle that should be pointed in the -x and +y direction not the opposite? Like if I had a pair of pliers and I only press down on the upper that would make the mouth push up.
 
doubled said:
Oh thanks a lot. So if we look at the top part wouldn't the 30lb force pointing down be applying a force on the circle that should be pointed in the -x and +y direction not the opposite?
Well yes, that's Newton's third law, the force of the pliers on the circle act to squeeze it . But when you draw the FBD of the pliers, the force of the circle thingy acting on the pliers points in the +x and -y direction (down and to the right), which you can show by summing moments about the pin.
if I had a pair of pliers and I only press down on the upper that would make the mouth push up.
Well, you can't just press down on the upper part, you have to sqeeze the handles together with an equal but opposite force on each in order to make the thing work. The lower jaw moves up, and the upper jaw moves down, as if it were biting the 'circle' (a nut or bolt or rod, etc).:eek:
 
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