Since $\overline{AD}\parallel\overline{BC}$, and the trapezoid is cyclic, we know it must be isosceles. So we know $\angle A=60^{\circ}$, if $\measuredangle C=120^{\circ}$.
Thus, we know:
$$\angle E+\angle F=60^{\circ}$$
If we label the two angles at vertex $B$ as $G$ and $H$, we then know:
$$\angle G+\angle H=120^{\circ}$$
Can you find two more equations involving these 4 angles? Hint: add the interior angles of the two triangles making up the trapezoid...:D
Also, to simplify matters, $G$ and $H$ must share a special relationship to $E$ and $F$. ;)