Can the B field be obtained from the magnetic potential using matrix inversion?

[sinyud]

How do you get the B field from the magnetic potential?
I tried converting the curl into matrix format, but the corresponding matrix can't be inverted.

 

[Tide]

It's just the curl of the vector potential:

\vec B = \nabla \times \vec A

I'm not sure what you're tyring to do with it.

 

[sinyud]

I got it backward. How do you the A field from a B field?

 

[Tide]

Oh! Well in that case ... it depends on what problem you're trying to solve. Check with a good E&M book for some discussion on Green's functions. That might help. It's been a while since I worked with that so I'd have to review it myself.

 

[Dr Transport]

\vec{A} = \pm \frac{1}{2} \vec{B} \times \vec{r} if memory serves me correctly...

 

[Tide]

Thanks, Dr. T! Sinyud could easily check that by calculating the curl.