Can the Length of a Curve be Simplified Using Trigonometric Identities?

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Homework Statement



length of curve r=(1+cos(2 theta))^(1/2) from -pi/2..pi/2

Homework Equations



L= integral sqrt(r2+(dr/d(theta))2

dr/d(theta)= -sin(2theta)-sin(2theta)cos(2theta)

The Attempt at a Solution


this integral seems ways to complicated is there something to simplify it?

dr/d(theta)= -sin(2theta)-sin(2theta)cos(2theta)
then squaring it and adding (1+cos(2 theta))
seems really hard to integrate. So if someone could point out what I'm doing wrong, that would be nice. thanks.
 
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When you see cos 2θ that should remind you of something - if not look up a table of trig identities, or even work it out - and I think you can simplify this problem.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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