Can the Midpoint Between Two Equal Circles Ensure Symmetric Area Division?

  • Thread starter Thread starter ritwik06
  • Start date Start date
  • Tags Tags
    Areas Circles
AI Thread Summary
The discussion revolves around proving that the midpoint between two equal circles is the only point through which arbitrary lines can be drawn to ensure equal area division on either side. The poster struggles to formulate a formal proof and seeks assistance, noting that while the concept seems intuitive, proving it is challenging. They suggest considering special cases, such as points inside or outside the circles, and the implications of drawing tangents. The need for a rigorous proof suitable for an exam context is emphasized. The inquiry highlights the complexity of geometric proofs involving symmetry and area division.
ritwik06
Messages
577
Reaction score
0

Homework Statement


There are two circles of equal radii. I have to prove that the mid point of the line joining their centres is the only point through which if several arbitrary lines are drawn, equal areas enclosed by the circles will fall on either side of the line.

I cannot think of a way to proceed. I have observed the situation by drawing out equal cirlces and testing the conditions. They seem as obvious as the result of 2+2, but equally difficult to prove.
Please help .
 
Physics news on Phys.org
Pick a point that is NOT the midpoint. Can you see a way to construct a line through it that does NOT cut the circles generating equal areas? Hint: you may want to consider some special cases. Suppose the point is inside one of the circles? Suppose it's in neither? In the latter case case can you show that if you draw the two lines tangent to one circle that they aren't also tangent to the other? Then think about rotating the line 'a little'.
 
Dick said:
Pick a point that is NOT the midpoint. Can you see a way to construct a line through it that does NOT cut the circles generating equal areas? Hint: you may want to consider some special cases. Suppose the point is inside one of the circles? Suppose it's in neither? In the latter case case can you show that if you draw the two lines tangent to one circle that they aren't also tangent to the other? Then think about rotating the line 'a little'.

I just need a formal proof that would be accepted in an exam. I cannot go on with special cases. Thanks for the help though!
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

Similar threads

Back
Top