Can the spacing of rods affect the weight needed for applied force?

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SUMMARY

The discussion focuses on calculating the weight required to apply a specific force to a set of rods under two scenarios. In the first problem, ten rods, each with a diameter of 2mm and a length of 3cm, require a total weight of 500g (4.9N) to ensure each rod experiences a force of 0.49N. The second problem introduces a spacing of 2mm between the rods, raising questions about how this affects the required weight. The consensus is that while the spacing may seem to complicate the situation, the total weight needed remains the same as in the first problem.

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Hey guys, i need you help to find the weightof a mass required to produce the same applied force to rods.
(sorry english is not my first language) i will try to explain this with a diagram.

Homework Statement


First problem:
So let's say i have 10 small rods with a diameter of 2mm and a length of 3cm.
they are positioned next to each other, and stand on the ground. Then i have a weight that is applying force to those 10 rods alltogether. SO my question is, how much is the weight of the mass that i need, to make sure that every rods will be applied 50g(0,49N) each.

known values:
F(on each rods)= 0.49N or 50g
length of each rod=3cm
diameter or a rod=2mm

Problem 2:
Now its exactly the same as situation 1, but the rods are positioned at a distance from each other, let's say this distance is x=2mm
How much is the weight required for applying each rods the same force of 0.49N?


Homework Equations


g=9,81ms-2
1000g=1kg=9,81N

The Attempt at a Solution



Problem 1
For applying each rod 0.49N,
the mass should be= 10rodsx0.49N= 4,9N which is about 500g
i wish it would be that easy, but i think there's got to be something that is not right?

Problem 2
this is actually very confusing, so i can't really know how to go with it, would you guys help me?

Thanks!
 
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Seems like problem 1 is correct. Why would spacing the rods make a difference?
 

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