Skhandelwal said:
I was wondering, since there is no limit to how many points you can pick b/w x value 1 to 2. If you keep picking smaller and smaller values, the curve keeps getting more and more straight. It is similar to how .000000000...till infinity then 1 equals zero. So if that's true, don't you think it is possible for 3 collinear points to be there in a curve?
Yes, of course, it is possible, say you have a curve y = x
3, the 3 point (-1, -1), (0, 0), and (1, 1) are collinear, and on the curve.
Here, I'll be more specific, in a quadratic curve.
No there cannot be more than, or equal to 3 collinear points the lie on a quardratic curve. Why?
The function of a quadratic curve is: y = ax
2 + bx + c (a not 0)
And the function of a line is y = dx + e
Now if there are 3 points that both lie on the curse, and the line mentioned above, then there must be
3 distinct solutions to the equation:
ax
2 + bx + c = dx + e
<=> ax
2 + (b - d)x + (c - e) = 0
But that's a quadratic equation, and so, there are at most 2 distinct solutions. There cannot be 3.
Can you get this? :)