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Eitan Levy said:Homework Statement
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Homework Equations
The Attempt at a Solution
I wrote equations for the vertical and horizonal distances, but I still wasn't able to find L (was missing an equation).
Is it possible?
PeroK said:You need to show us how far you got.
As I see it, given the information, the ball can only land in one position, so it must be possible to solve the problem.
PS I think you are supposed to assume energy conservation from the angle of incidence being equal to angle of reflection.
gneill said:You'll need to provide the details of your work.
It's certainly possible to use kinematic equations to find the result. The acceleration due to gravity is a constant value, hence the constant acceleration kinematic formulae all apply (SUVAT).Edit: Ah! @PeroK got there ahead of me!
We solved this problem in class before we studied energy, so my teacher either used it to introduce the topic to us or solved it without it.PeroK said:You need to show us how far you got.
As I see it, given the information, the ball can only land in one position, so it must be possible to solve the problem.
PS I think you are supposed to assume energy conservation from the angle of incidence being equal to angle of reflection.
You can use the first equation to find an expression for ##t##. You can substitute that along with the known values for sin(30), cos(30), and V into the second equation to yield an equation with only one unknown, ##L##.Eitan Levy said:Now let's say that the ball leaves the surface with a velocity equals to V.
We can say that:
Lcos(30)=Vcos(30)t
-Lsin(30)=Vsin(30)t-5t2.
We see at the end that V=5t, and that L=0.2V2.
We also know that the ball hits the surface with a velocity of √(20), all vertical.
Now I am stuck.
Didn't you use energy considerations if you assumed that the velocity stays the same after the ball hits the surface?gneill said:You can use the first equation to find an expression for ##t##. You can substitute that along with the known values for sin(30), cos(30), and V into the second equation to yield an equation with only one unknown, ##L##.
Eitan Levy said:First we can know this:
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Now let's say that the ball leaves the surface with a velocity equals to V.
We can say that:
Lcos(30)=Vcos(30)t
-Lsin(30)=Vsin(30)t-5t2.
We see at the end that V=5t, and that L=0.2V2.
We also know that the ball hits the surface with a velocity of √(20), all vertical.
Now I am stuck.
PeroK said:I think you've almost got it. You have:
##L = 0.2 V^2##
I assume that is with ##g =10m/s^2##.
And, you have got ##V = \sqrt{20} m/s##
So, that's it isn't it? It bounces off the triangle with the same speed ##V## as it hit it. Just in a different direction.
Eitan Levy said:What I am asking is how you know that the velocity stays the same after it hits the surface.
Alright, thanks a lot.PeroK said:Two reasons. 1) That's a property of angle of incidence = angle of reflection. 2) If you assume variable ##V## after the bounce, then the problem can't be solved! ##L## would depend on a thing called the coefficient of restitution.
In a way, yes: I made the practical assumption of it being a perfectly elastic collision. There was nothing in the problem statement that would suggest otherwise. See also @PeroK 's response.Eitan Levy said:Didn't you use energy considerations if you assumed that the velocity stays the same after the ball hits the surface?
To expand a little on @PeroK's reply...Eitan Levy said:What I am asking is how you know that the velocity stays the same after it hits the surface.
This depends on the specific problem at hand. In some cases, it may be possible to find a solution without taking energy into account. However, in many cases, energy considerations are essential for understanding and solving the problem.
Problems that do not involve physical systems or phenomena, such as mathematical or conceptual problems, may not require energy considerations. However, for problems involving physical systems, energy is often a key factor in finding a solution.
In many cases, it is crucial to consider energy when solving a problem. Energy is a fundamental concept in science and plays a significant role in understanding and predicting the behavior of physical systems.
There may be alternative methods for solving certain problems without explicitly using energy considerations. However, these methods may still indirectly involve energy concepts or rely on similar principles.
Considering energy can provide valuable insights into a problem and help determine the most efficient or effective solution. It can also help identify any limitations or constraints that may affect the solution.