Can Total Energy Be the Same in Liquid and Vapour Phases at Equilibrium?

AI Thread Summary
At the boiling point, a liquid and its vapor are in equilibrium, meaning they exert equal pressure. The total energy of the two phases is indeed the same, despite differences in kinetic and potential energy. While kinetic energy may differ due to molecular motion, the total energy remains constant because energy is required to change phases. The discussion emphasizes that equilibrium does not imply identical energy states but rather a balance in energy exchange. Understanding this concept is crucial for grasping phase transitions and thermodynamic principles.
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Homework Statement


A liquid is in equilibrium with its vapour at it’s boiling point. On the average, the molecules in the two phases have equal;; provided options are:
a. inter-molecule forces
b.potential energy
c .Kinetic energy
d.total energy

.

Homework Equations

The Attempt at a Solution

:
Answer is Total energy
I am unable to understand that since vapour and liquid phases are in equilibrium that means they are exerting similar pressure which means kinetic energy should be same also how can both of them have same energy if they are in different phases?
Can you please tell me how can total energy be same in this question
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It can't. You have to put energy into a liquid to evaporate it.
What is the same between two phases in equilibrium? How is this related to any of the options you are given?
 
The question asks for what kind of force / energy can be possibly similar in liquid and vapour phase of the atom/molecule in state of equilibrium.
 
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