- #1
chetan
How to find out the mass of Mercury & Venus
Can We Determine the Mass of Mercury and Venus Using Space Probe Orbits?
AI Thread Summary
To determine the masses of Mercury and Venus, direct searches on Google yield immediate results, such as the mass of Venus being approximately 4.86900 × 10^24 kilograms. Google also offers various functions, including unit conversions. However, the discussion shifts to the empirical methods for finding the masses of these planets, noting that they lack moons, which complicates traditional measurement methods. It is suggested that artificial satellites may be used to measure their masses, although specific methods remain uncertain. The conversation highlights the power of Google for quick information retrieval while acknowledging the challenges in empirical measurements of planetary masses.
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Hello!
I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below.
Here is how I wrote the condition of equilibrium forces:
$$
\begin{cases}
F_{g\parallel}=F_{t1}+F_{t2}, \\
F_{g\perp}=F_{r1}+F_{r2}
\end{cases}.
$$
On the other hand...
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