Can You Calculate How Long it Takes to Drain a Car Battery with Headlights On?

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The discussion revolves around calculating the time it takes to drain a 60 Ah car battery with headlights and parking lights on. The total power consumption is calculated at 140 W from two main headlights and four parking lights. The battery's total charge is established as 216,000 C. Participants suggest that knowing the battery's voltage is crucial for determining current and ultimately the time to discharge. A solution link is referenced, indicating that the problem may not be as complex as initially thought.
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Homework Statement


The headlights on a car operate typically at 60 W and the parking lights typically at 5 W. Assuming that there are two main headlights and four parking lights, what length of time will it take to discharge a 60 Ah battery, if the lights are left on?

Homework Equations


I = Q/t

V = W/Q

P = W/t

P = I2*R

P = V2/R

P = IV

The Attempt at a Solution


I have gotten no where with this question. :frown:

All that I could do was find that the total power consumed by the lights:

PT = (2*10) + (4*5) = 140 W

, and the charge of the battery:

1 Ah = 3600 C
∴ 60 Ah = 216,000 C

, and that's it.

I have tried simultaneous equations by substitution and elimination but that doesn't work because all of the equations are derived from the base equations I = Q/t, V = W/Q and P = W/t, so I end up getting P = P all the time.

Hint's anybody?

Thank you.
 
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Not sure, but maybe you are suppose to assume that the voltage of the battery is the typical voltage for a car battery.
 
You need the voltage of the car battery to find the current. Look at Automotive battery - Wikipedia, the free encyclopedia, or just see the battery in your car...

ehild

FredericChopin said:

Homework Statement


The headlights on a car operate typically at 60 W and the parking lights typically at 5 W. Assuming that there are two main headlights and four parking lights, what length of time will it take to discharge a 60 Ah battery, if the lights are left on?


Homework Equations


I = Q/t

V = W/Q

P = W/t

P = I2*R

P = V2/R

P = IV

The Attempt at a Solution


I have gotten no where with this question. :frown:

All that I could do was find that the total power consumed by the lights:

PT = (2*10) + (4*5) = 140 W

, and the charge of the battery:

1 Ah = 3600 C
∴ 60 Ah = 216,000 C

, and that's it.

I have tried simultaneous equations by substitution and elimination but that doesn't work because all of the equations are derived from the base equations I = Q/t, V = W/Q and P = W/t, so I end up getting P = P all the time.

Hint's anybody?

Thank you.
 
Hmm... It seems like it... Based on this link, which is the worked solution to the question.

Thank you TSny and ehild.

So much for "complex, challenging and novel"... :rolleyes:
 
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