Can you guys check these calculations for me

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The calculations for the kinetic energy of a .50 cal round from a Barrett M82 rifle indicate that each round generates approximately 16.9 kJ of energy, totaling around 170 kJ for a full clip of 10 rounds. The energy required to raise the temperature of a blob, composed of 75% adipose tissue and 25% other body tissue, by 1 degree Celsius is calculated to be 1,039 kJ. This results in a temperature increase of only 0.016 degrees Celsius when considering the kinetic energy from the rounds. A correction was noted in the calculations, clarifying that "KE" should be used instead of "PE." Overall, the calculations demonstrate the significant difference between the energy produced by the rounds and the energy required to affect the blob's temperature.
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Background Information:
Clip Capacity of a Barret M82: 10 Rounds
Mass of a .50 Cal Round: 46.7 grams = .0467 Kg
Source: small arms by martin j. dougherty
Average Muzzle Velocity of a Barret M82 .50 Cal Rifle: 853 m/s
Average Specific heat capacity of normal human tissue: 3470 J/kg.C
http://www.engineeringtoolbox.com/human-body-specific-heat-d_393.html
Average Specific heat capacity of Adipose tissue: 2348J/kg.C
Source: http://www.itis.ethz.ch/itis-for-health/tissue-properties/database/heat-capacity/
Weight of Blob: 976 lbs = 442.7 Kg

Assumptions: Blob is around 75% adipose tissue(by weight) the remaining being normal body tissue. This means 332 Kg is adipose tissue. 110.6 Kg is other misc. body tissue.
Important Formula:
Kinetic Energy: Pe= ½mv2

Calculations:

Ke= 1/2 (.0467 Kg)(853 m/s)2 = 16.98 Kj = 16980 J

Joules needed to Raise blob 1 Degrees Celcius:
(332 Kg * 2348 J/Kg) + (2348J/Kg * 110.6 Kg)= 779536J + 259688J= 1039224 J = 1039 Kj
How much does Blob’s Temperature increase? : 19.98/ 1039 = .016 degrees Celcius
 
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Pe= ½mv2

That should be "KE" not PE but otherwise looks ok.

I made the KE of each round..

= 0.5 * .0467 * 8532 = 16.9 kJ not 19.98 kJ

There are 10 rounds so the energy is about 170 kJ.
 

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