Can You Solve These Advanced Calculus Integrals?

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SUMMARY

This discussion centers on the integration of two advanced calculus problems: the integral of \(\frac{dx}{x^3+x^2+x+1}\) and the definite integral \(\int_{\frac{\pi}{2}}^{\pi} \left( \sin(x) \ln(x) - \frac{\cos(x)}{x}\right) dx\). The first integral is solved using partial fraction decomposition, while the second requires integration by parts. The conversation also highlights forum rules against posting homework-like questions, emphasizing the importance of adhering to community guidelines.

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  • Understanding of advanced calculus concepts, specifically integration techniques.
  • Familiarity with partial fraction decomposition.
  • Knowledge of integration by parts.
  • Basic understanding of complex logarithms and their properties.
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Ratio Test =)
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Hello :)
Here we go! :


1. <br /> \int \frac{dx}{x^3+x^2+x+1}<br />

2. <br /> \int_{\frac{\pi}{2}}^{\pi} \left( sin(x) ln(x) - \frac{cos(x)}{x}\right) dx<br />

Do your best :)
 
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1 + x + x^2 + x^3 = (1-x^4)/(1-x)

So, we have to integrate -(x-1)/(x^4 - 1)

The singularities of this function are at x = -1, i and -i, so the partial fraction decomposition is:

-1/2 1/(x+1) +1/4 (1+i)/(x-i) + 1/4 (1-i)/(x+i)

The integral is thus given by:

-1/2 Log(x+1) + 1/4 (1+i)Log(x-i) + cc of last term. =

-1/2 Log(x+1) + 1/2 Re[(1+i)Log(x-i)]

Real and imaginary parts of logarithms of complex arguments are easily obtained as follows. We have:

Log[r exp(i theta)] = Log(r) + i theta

This means that:

Log(x + i y) = 1/2 Log(x^2 + y^2) + i arctan(y/x)

The integral is thus given by:

-1/2 Log(x+1) + 1/4 Log(x^2 + 1) + 1/2 arctan(1/x)

-1/2 Log(x+1) + 1/4 Log(x^2 + 1) - 1/2 arctan(x)

(pi absorbed in integration constant which we don't write down)
 
Last edited:
Um, I believe #1 is just partial fractions, while #2 is integration by parts. No need to be fancy :)
 
sin(x)ln(x)-cos(x)/x=(-cos(x))'ln(x)+(-cos(x))(ln(x))'=(-cos(x)ln(x))'
 
Ratio Test =) said:
Hello :)
Here we go! :


1. <br /> \int \frac{dx}{x^3+x^2+x+1}<br />

2. <br /> \int_{\frac{\pi}{2}}^{\pi} \left( sin(x) ln(x) - \frac{cos(x)}{x}\right) dx<br />

Do your best :)


Welcome to the PF, Ratio. We generally do not allow homework-like brain teasers here on the PF, for obvious reasons. Please do not post this type of question again. I've moved this question to the Homework Help forums, and the normal homework rules apply (we don't do these types of questions for students).
 
berkeman said:
Welcome to the PF, Ratio. We generally do not allow homework-like brain teasers here on the PF, for obvious reasons. Please do not post this type of question again. I've moved this question to the Homework Help forums, and the normal homework rules apply (we don't do these types of questions for students).


One Question : Who told you this is for my homework ?
Did you read the thread's title ?
 
Ratio Test =) said:
One Question : Who told you this is for my homework ?
Did you read the thread's title ?

Don't imply I'm an idiot. If you don't understand why homework questions aren't allowed as brain teasers, please think about it a bit more. And re-read the PF Rules link at the top of the page that you agreed to when you joined here.

Thread locked. Show some brains people.
 

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