Can you verify my Physics work please?

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The discussion revolves around verifying physics calculations related to motion and acceleration. The user seeks confirmation on their solutions for two problems involving stopping distance and average speed. For the stopping scenario, they calculated the average speed and time taken to stop, but received feedback suggesting a different formula for acceleration. In the second scenario, they correctly found the average speed and acceleration but were advised to use more conventional units for clarity. Overall, the calculations were generally accepted, with minor suggestions for improvement.
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I am preparing for a physics test and i want to make sure what and how I am solving the review questions is correct because I have no answer key!Thank you in advance!

2-You are driving in your car at a steady 80.0km/h. and you suddenly see a stop sign. You apply your breakes and stop after 60.0m(or 0.06km).

a)How long did it take you to stop?
What I did was find Vavg=0.5(80.0km/h + 0.0km/h) then using it in the equation of delta d=Vavg.*delta t and getting an answer of 0.0015h.

b)What was your acceleration?
What I did was using the formula V2^2=V1^2+2a(delta d) and I solved to get a= (to appropriate sig fig) -53300km/h^23-During the span of 5.0s time interval an object begins at 5.0m/s, accelerates uniformly and ends at 20.0m/s.

a) What is the average speed of the obect in this 5 s interval?
What I did Vavg=0.5(20.0m/s + 5.0m/s)=12.5m/s

b)What is the acceleration?
What I did v2=v1+2a(t)
20.0m/s=5.0m/s+2a(5.0s)
a= 3.0m/s^2
Thank you again!
 
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I would choose a different formula for 2b (you already know the velocity difference and the time), but that one is possible as well.
m/s and m/s^2 would be more conventional units for the answers. I did not check the numbers, a computer can do this quicker.

3 is fine.
 
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