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mattmannmf
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Dumb moment here...I have the following equation:
Sin (4/(3x+3)) / Sin (4/3x)= 1
can i cancel out the sin's?
Sin (4/(3x+3)) / Sin (4/3x)= 1
can i cancel out the sin's?
mattmannmf said:Dumb moment here...I have the following equation:
Sin (4/(3x+3)) / Sin (4/3x)= 1
can i cancel out the sin's?
As long as a isn't 0 you can do this:mattmannmf said:Dumb moment here...I have the following equation:
Sin (4/(3x+3)) / Sin (4/3x)= 1
can i cancel out the sin's?
mattmannmf said:Dumb moment here...I have the following equation:
Sin (4/(3x+3)) / Sin (4/3x)= 1
can i cancel out the sin's?
mattmannmf said:Dumb moment here...I have the following equation:
Sin (4/(3x+3)) / Sin (4/3x)= 1
can i cancel out the sin's?
Does this mean I can't do this...rs1n said:The letters s-i-n in [itex]\sin(x)[/itex] are not variables. Those three letters together stand for an operation -- namely the operation of computing the sine of x. Similarly, we use the "+" symbol to refer to the operation of adding two values.
"Canceling" is the notion of dividing out by a common nonzero number, or by a common variable that stands for a nonzero number. "sin" is not a variable; it is an operation. Canceling is not a matter of "deleting letters and symbols" that appear in both the numerator and denominator.
jrlaguna said:Yeah, so funny... ;)
But if you want the limit, still can't cancel the sin's (cancel the sins... what would a priest think?) :P But you can do the obvious thing, try to substitute. You get sin(0)/sin(0) so, 0/0... why don't you try now L'Hôpital?
Susanne217 said:There this Wiki-link here
http://en.wikipedia.org/wiki/L'Hôpital's_rule
which gives some good examples on howto use L'Hospitals rule. Something which is a bit strange is that why is it to become a famous mathematician you have to so strange names? ;)
Only mathematician with a easy name to remember is Niels Henrik Abel and Cauchy.
:D Susanne
Char. Limit said:I'd also include Euclid, Newton, Leibniz, and Neumann on that list, but in general I think you're right. I still can't remember how to spell Ramananan, and he seems to have done everything he can with numbers.
jrlaguna said:You know the sense of humour of physicists... so when you come up with an important equation, this thread will come up and they will call it the Susanniwitz equation, no matter what your wishes are by then! Sorry, darling, you're dooooomed! :) :) :)
jrlaguna said:Yeah, funny as it is the other discussion, let us focus, boys and girls, ok? :)
In this case, the limit does exist, the conditions on the theorem are met. Promised. The question poser has to work it out, though. (This is homework help.)
The funny thing is I tested this problem on the equation-solver on old TI-92 and it claims that there are several solutions to the OP problem like the solutions are polynomial...
Cyosis said:Your calculator is correct. Don't forget that if you have an equation of the type sin(x)=sin(y) then x=y+2pi*k is a solution for k an integer.
The sin in this equation cannot be canceled because it is not present. It is likely that you are confusing the terms "sin" and "x". In this equation, "x" is the variable and cannot be canceled.
To simplify this equation, you can first rewrite it as (4/3x) / (4/(3x+3)) = 1. Then, you can use the reciprocal property to rewrite it as (4/3x) * (3x+3)/4 = 1. Finally, you can simplify by canceling out the 4s and multiplying the fractions to get 3x+3 = 4, which can be solved for x.
No, the distributive property cannot be used to cancel terms in this equation. The distributive property is used to simplify expressions with parentheses, but in this equation, there are no parentheses to distribute.
There is no specific rule for canceling terms in this equation. The best approach is to rewrite the equation in a simpler form, as shown in question 2, and then use basic algebraic principles to simplify and solve for the variable.
Yes, you can cancel out the denominators in this equation, but only after rewriting it in the form (4/3x) / (4/(3x+3)) = 1. Then, you can use the reciprocal property to rewrite it as (4/3x) * (3x+3)/4 = 1 and simplify from there.