Cannot understand what this proposition is saying

Thread starter rxh140630
Start date Nov 1, 2021

AI Thread Summary

A participant expresses confusion about how a straight line can have sides, prompting frustration with the topic. Another contributor clarifies that a vertical line indeed has a left and right side when viewed in a two-dimensional space. The original poster mentions that a figure in their book contributed to their misunderstanding. The discussion highlights the challenges of interpreting geometric concepts. Overall, the conversation centers on clarifying the definition of sides in relation to straight lines.

Nov 1, 2021

rxh140630

Homework Statement: On the same straight-line, two other
straight-lines equal, respectively, to
two (given) straight-lines (which meet)
cannot be constructed (meeting) at a
different point on the same side (of
the straight-line), but having the
same ends as the given straight-lines

Relevant Equations: Euclids element's

can someone please explain to me how a straight line has a side? this is so frustrating

Physics news on Phys.org

Nov 1, 2021

rxh140630

never mind I guess this thread might as well be deleted now.

Draw a vertical line, there is going to be a left side and a right side.

The figure that comes with the book confused me into questioning such a simple thing

Thread 'Finding the number of ways to arrange identical balls in a circle (3 different colors)'

I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks

View full post »

Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

View full post »