Can't seem to get the correct acceleration

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The discussion centers on calculating acceleration from a position vs. time graph, where the user derived two velocities of 390 cm/sec and 486 cm/sec. They calculated acceleration using the difference in velocities over a time interval of 0.015 seconds, resulting in an unexpectedly high value of 64 m/s^2, while the expected value for free fall is approximately 9.80 m/s^2. Participants suggest verifying the graph scale and consider that using a different time interval, such as 0.1 seconds, could yield a more reasonable acceleration. The need for accurate graph interpretation and calculation methods is emphasized to resolve the discrepancy. Clarifying these points is essential for achieving the correct acceleration value.
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From a position vs. time graph I calculated the slope of 2 tangent lines which is the velocity. The first slope was 390 cm/sec and the second slope was 486 cm/sec. Now to get the acceleration I thought I take difference of the velocities divided by the time interval 0.9 (1/60 sec) or 0.015sec. After calculations I got an acceleration of 6,400 cm/sec^2 which would be 64m/s^2. The only thing is that the acceleration should be close to 9.80m/s^2 because it was a free falling object and I need to find percent error. What am I doing wrong because I should be getting around 9.80m/s^2 and not such a large number like 64.
 
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It might help if you could post the graph you're working from. From working out the difference of the slopes one gets an answer of 96 which would get you a reasonable answer if the time interval was 0.1s. Are you sure you're reading the graph scale correctly?
 

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