Can't simplify equation into form (RLC)

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Discussion Overview

The discussion revolves around simplifying an equation related to RLC circuits, specifically focusing on algebraic manipulation to achieve a desired form. Participants are attempting to clarify their understanding of the algebra involved in the simplification process.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses uncertainty about how to simplify the equation into the required form.
  • Another participant suggests starting with the expression ## 1/(j \omega C)=-j/(\omega C) ##, indicating that the initial steps are correct.
  • Multiple participants reiterate the importance of algebraic manipulation, specifically multiplying by ## j/j ## to simplify terms involving ## 1/j ##.
  • There is a discussion about how to handle the terms in the numerator and denominator, with one participant noting that the resistance (R) remains in the denominator, complicating the simplification.
  • One participant mentions an edited suggestion that they believe makes the process simpler, but another participant expresses continued confusion about the application of this suggestion.
  • Finally, a participant claims that a specific manipulation leads to the correct answer, although the details of this manipulation are not universally agreed upon.

Areas of Agreement / Disagreement

Participants generally agree on the algebraic steps needed to simplify the equation, but there is no consensus on the specific approach to take or on how to fully resolve the remaining terms. Some participants express confusion and uncertainty about the process.

Contextual Notes

There are unresolved mathematical steps and dependencies on the specific definitions of terms involved in the equation. The discussion reflects a range of understanding among participants regarding the algebraic manipulations required.

Who May Find This Useful

This discussion may be useful for students or individuals working on problems related to RLC circuits and algebraic simplifications in electrical engineering contexts.

CoolDude420
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Homework Statement



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The answer in (algebraic form) is
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Homework Equations

The Attempt at a Solution



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I'm not sure how to simplfy into the form required from here.
 
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Suggestion: To start, ## 1/(j \omega C)=-j/(\omega C ) ##. What yo have is correct so far. The rest is just algebra.
 
Charles Link said:
Suggestion: To start, ## 1/(j \omega C)=-j/(\omega C ) ##. What yo have is correct so far. The rest is just algebra.

cc08e2c6ff.png
 
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You are almost there. When you have a ## 1/j ## multiply by ## j/j ## and you get ##-j ##. That gives you ##-j \omega L/(\omega^2 LC-1) ##. Then just multiply through upstairs and downstairs by ## 1-\omega^2 LC ##.
 
Charles Link said:
You are almost there. When you have a ## 1/j ## multiply by ## j/j ## and you get ##-j ##. That gives you ##-j \omega L/(\omega^2 LC-1) ##

Yeah, that's what I got too now. Not sure how I'm going to get all those terms on the top like in the final answer. The R is still in the denomintor so I can't even flip and multiply
 
See my edited post 4. It's simple.
 
Charles Link said:
See my edited post 4. It's simple.

Sorry about this. I still can't seem to get it through my head. Do you mean multiply the entire fraction(including the Vs) above and below by that or do I just multiply the fraction in the denomiator by that. I tried both and I'm still getting stuck :(

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OR

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The second way, and it immediately gives you the correct answer ! ##- j \omega L (1-\omega^2LC)/(\omega^2 LC-1)=j \omega L ##.
 
Charles Link said:
The second way, and it immediately gives you the correct answer ! ##- j \omega L (1-\omega^2LC)/(\omega^2 LC-1)=j \omega L ##.

Ah! I see. Thank you! It's always the algebra problems..
 
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