Capacitance of an asymmetrical parallel plate capacitor

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SUMMARY

The capacitance of an asymmetrical parallel plate capacitor, such as one with a 1" diameter plate and a 4" diameter plate, can be approximated as similar to that of two identical plates due to the perpendicular nature of most electric field lines. However, to accurately account for edge effects, numerical methods must be employed. The complexity arises from the need to solve integrals over the electric field volume, particularly when considering the varying plate sizes. Resources like HyperPhysics provide examples and approaches for calculating capacitance in such scenarios.

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nickexists
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I've been looking all over and to my great surprise have not be able to find an answer to this question.

What is the capacitance between to parallel plates if one plate is larger than the other? For example, the capacitance between a 1" diameter plate and a 4" diameter plate.

Thanks.
 
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The math gets quite tricky when you have situation like that. As a first approximation the capacitance would be nearly the same as for two identical plates (since most of the E-field lines will be perpendicular to the plates). However, if you want to take edge effects into account the calculation becomes tricky and in the "real world" you would probably have to solve this numerically.
 
Thanks. I am actually interested in how this works out in the real world, do you know more specifically how I would go about solving this numerically?
 
nickexists said:
What is the capacitance between to parallel plates if one plate is larger than the other? For example, the capacitance between a 1" diameter plate and a 4" diameter plate.
If the plates are close enough, the capacity will be very close to the capacitor of both plates plates being 1" dia
 
A tricky integral over the volume of the E field... i don't know how one would establish outer bound.
See hyperphysics example of a spherical capacitor , for an approach...
 

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