- #1
Robertphysics
- 16
- 4
HiI’ve been reading for a while and decided to ask , suppose we have a parallel plate capacitor with a distance x between the plates , in between the plates are another two plates with a dielectric so in total 4 plates. The outer two are attached to a dc supply of 12volts for example.
Now I understand that charge on the plates is given by their separation distance , surface area and the dielectric between them , what I don’t know for sure is what happens in the middle two plates in my example that are not attached to a power source ,
They will get charge on them as well I suppose and the dielectric in the middle will get polarized two , as far as I understand inserting such two plates in the middle is effectively putting another capacitor in series.
I want to know what happens on the two plates in the middle of the outer two which are attached to DC. I suppose the inner plates mimic the outer ones in terms of charge separation and + and – sides just that the charge on them is weaker because they are at a distance away?What would happen if I removed the inner plates with their dielectric , would they hold their charge just like any other parallel plate cap that has been charged , I suppose they should.My final question for now is this , what happens when I have my 4 plates , outer ones attached to DC , inner ones floating , now I charge the cap , then I connect a load like a light bulb between the inner ones , would the lightbulb flash as the charge flows through the load from plate to plate , and what would happen afterwards when my outer plates are still connected to DC but the inner ones have been attached to a load?
Now I understand that charge on the plates is given by their separation distance , surface area and the dielectric between them , what I don’t know for sure is what happens in the middle two plates in my example that are not attached to a power source ,
They will get charge on them as well I suppose and the dielectric in the middle will get polarized two , as far as I understand inserting such two plates in the middle is effectively putting another capacitor in series.
I want to know what happens on the two plates in the middle of the outer two which are attached to DC. I suppose the inner plates mimic the outer ones in terms of charge separation and + and – sides just that the charge on them is weaker because they are at a distance away?What would happen if I removed the inner plates with their dielectric , would they hold their charge just like any other parallel plate cap that has been charged , I suppose they should.My final question for now is this , what happens when I have my 4 plates , outer ones attached to DC , inner ones floating , now I charge the cap , then I connect a load like a light bulb between the inner ones , would the lightbulb flash as the charge flows through the load from plate to plate , and what would happen afterwards when my outer plates are still connected to DC but the inner ones have been attached to a load?