Capacitor and Switch Potential Difference Calculations

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Homework Help Overview

The discussion revolves around a circuit involving capacitors and a switch, with an initial potential difference of +210V applied. Participants are exploring the effects of closing the switch on the potential differences across the capacitors and the charge flow through the switch.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to visualize the circuit behavior when the switch closes and are questioning the impact on the potential differences and charge distribution across the capacitors.

Discussion Status

Some participants have made progress in calculating the potential difference between points c and d, while others emphasize the importance of establishing initial conditions before addressing subsequent parts of the problem. There is an ongoing exploration of how to represent the circuit and the charges on the capacitors.

Contextual Notes

Participants are discussing a DC circuit setup with capacitors, noting that any current flow will be transient as the capacitors charge. There is a focus on understanding the initial voltages and charges before the switch is closed.

burnst14
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Homework Statement


The switch is initially open and the capacitors are uncharged. The applied potential difference Vab = +210V.
a.) What is the potential difference Vcd?
b.) What is the potential difference across each capacitor when the switch is closed?
c.) How much charge flowed through the switch when it was closed?

Homework Equations


I'm thinking this will be all I need:
Q=CV

3. The Attempt at a Solution
I can't even visualize what happens when the switch closes, so I'd like to start there. When the switch closes, more current will divert to the bottom capacitor since it will offer less resistance, but my solution manual says it changes the entire circuit setup.
I've attached the problem statement and the solution manual setup statement.
Screenshot_2015-02-15-14-58-00.png
Screenshot_2015-02-15-14-59-26.png
 
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You do realize that this is a DC setup with capacitors as the load, right? So any current that flows will be a momentary transient while the capacitors charge or change charge to a new steady-state. There are no resistances in the circuit.

Have you worked out the initial voltages and charges on all the capacitors prior to the switch closing? It doesn't make sense to start at part (b) if you haven't established the initial conditions for part (b) to take place.
 
Okay so, heeding your advice, I solved part (a). I got a potential difference of +70 V from point c to point d.

Now, closing the switch, what happens? I still can't picture it.
 
burnst14 said:
Okay so, heeding your advice, I solved part (a). I got a potential difference of +70 V from point c to point d.

Now, closing the switch, what happens? I still can't picture it.
You won't picture it until you've labelled the diagram with the charges on each capacitor. I haven't seen your values for those charges.
 

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