Capacitor charge time, two conflicting answers

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The discussion centers on the confusion surrounding capacitor charging time calculations, highlighting two conflicting responses from a Quora post. One response suggests that energy loss during charging affects the time calculation, while the other emphasizes the need for a circuit diagram to clarify the context. Both answers ultimately arrive at the same formula, t = C*V/I, but the user struggles to reconcile the differing interpretations. The conversation suggests that understanding the charging method and circuit configuration is crucial for accurate calculations. Clarifying these concepts can resolve the confusion regarding capacitor charge time.
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Help me correctly determine cap charge time
While attempting to calculate capacitor charging time I came across two conflicting concepts. I think my confusion can be pretty much summed up by the top two responses to this quora post:

https://www.quora.com/How-can-I-cal...-the-charging-current-voltage-and-capacitance
Pasted below for convenience.

I understand the first guy's response results in a time value that is half of the answer provided by the assistant bot. That comes from the energy loss of charging the capacitor being a factor of 2(we lose half our power to heat and other losses when charging a cap). But I am having trouble coming up with the why/how through the use of a proof. There is something that he is missing when integrating the current with respect to time but I cannot figure out what.

Answer 1:
1755830338579.webp

Answer 2:
1755830381909.webp
 
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rad_controls said:
Help me correctly determine cap charge time
It depends on how you charge the capacitor.
You need a circuit diagram for context.

Given constant i and constant C.
C = Q / V ; definition of capacitance.
Q = i ⋅ t ; charge.
C = i ⋅ t / V ; ∴ t = C ⋅ V / i .
V / t = i / C ; ∴ dv/dt = i / C .
 
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Baluncore said:
You need a circuit diagram for context.
Especially since it's often about a voltage source with a resistor or: with an impedance...
 
Yes. Typically you will not be charging a capacitor with a constant current.
 
Charging a capacitor with constant current has been used many times in timing circuits.
 
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Gordianus said:
Charging a capacitor with constant current has been used many times in timing circuits.
Yep. CRT scopes did this to generate the sweep voltage. I've been involved in a few of those designs. Relatively slow sweep speeds for NTSC waveform monitors. Although I did troubleshoot higher speed scopes for a few years.
 
rad_controls said:
TL;DR Summary: Help me correctly determine cap charge time

While attempting to calculate capacitor charging time I came across two conflicting concepts. I think my confusion can be pretty much summed up by the top two responses to this quora post:
The answers are the same. both give t = C*V/I. I don't understand what the problem is
 

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