Capacitor Diagram Transormations

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dwn
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I am having a difficult time understanding how they're transforming this capacitor schematic...what exactly is going on here? The example states that each cap is 7pF and the final answer C(eq) = 4.308pF...but why?
 
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  • Circuit schematic of a ladder network with four vertical branches, each containing one component, joined by horizontal wires between two rails, with two rectangular components along the bottom rail.
    Screen Shot 2014-03-30 at 6.24.30 PM.jpg
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  • Circuit schematic of a network of rectangular elements arranged in a bridge-like pattern between two horizontal wires, with a text header asking to extend Delta-Y transformations with each element a 2 pF capacitor, rounding to three decimal places.
    Screen Shot 2014-03-30 at 6.24.17 PM.jpg
    10.1 KB · Views: 466
There should be 3 figures to illustrate what the dialogue is describing, The first figure would be identical to that in your image #2. Then the Y network at its centre is transformed to Δ, producing the figure you have as image #1.

Finally, to consolidate the topic, they set you an exercise to apply what you have learnt, and this exercise is centred around your image #2.

You'll need the formulae for these impedance transformations, presumably your lectures have covered the topic? http://www.allaboutcircuits.com/vol_1/chpt_10/13.html