Capacitor loop with no resistance ?

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Discussion Overview

The discussion revolves around a circuit simulation issue involving a capacitor loop with no resistance. Participants explore the implications of simulating a circuit with two capacitors in parallel and the limitations of the simulator being used.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that the two capacitors in parallel should function as an equivalent capacitor without issues.
  • Another participant agrees that the circuit itself is not inherently wrong but points out that the simulator is designed for LRC circuits, not general-purpose simulations.
  • A different participant notes that the simulator's error message indicates a problem with current flow in a loop without resistance, which could complicate calculations.
  • It is proposed that adding a very small resistor could resolve the simulation issue, as real-life circuits always have some resistance.
  • One participant mentions that if the capacitors have different initial voltages, this could invalidate the circuit for simulation purposes unless resistance is included.

Areas of Agreement / Disagreement

Participants generally agree that the circuit design itself is not flawed, but there is disagreement regarding the simulator's limitations and how to address the issue of simulating a capacitor loop without resistance.

Contextual Notes

Limitations include the simulator's requirement for resistance in circuits with capacitors and potential issues arising from differing initial voltages across capacitors.

DocZaius
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"Capacitor loop with no resistance" ?

In Circuit Simulator at http://falstad.com/circuit/ I created a circuit attached below which refuses to run because "capacitor loop with no resistance". To me it seems that there is no problem with this circuit and that the two capacitors will simply act as an equivalent capacitor of capacitors in parallel. They would charge up and that would be the end of that. What am I missing? The reason I'm posting here is that I assume there is that this is due to my lack of understanding of the physics of the situation rather than some bug.
 

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Last edited:
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There's nothing "wrong" with your circuit. Your two 10uF capacitors in parallel are equivalent to a 20uF capacitor.

I guess the problem is that the simulator only works for LRC circuits. It's not a general purpose simulator like SPICE.
 


DocZaius said:
In Circuit Simulator at http://falstad.com/circuit/ I created a circuit attached below which refuses to run because "capacitor loop with no resistance". To me it seems that there is no problem with this circuit and that the two capacitors will simply act as an equivalent capacitor of capacitors in parallel. They would charge up and that would be the end of that. What am I missing? The reason I'm posting here is that I assume there is that this is due to my lack of understanding of the physics of the situation rather than some bug.
This is a limitation of the simulator - it's saying there is a path that current can go, which is from one capacitor to another, and then back to the first, never encountering any resistance. That messes up the calculations. In real life that never happens, because everything has a very small resistance, even wires.

This is resolved by adding a very small resistor to either one of the capacitors - you can make it 0.001 ohms, which is the resistance of half an inch of wire AWG26.
 


AlephZero said:
There's nothing "wrong" with your circuit. Your two 10uF capacitors in parallel are equivalent to a 20uF capacitor.

I guess the problem is that the simulator only works for LRC circuits. It's not a general purpose simulator like SPICE.

It has its limitations, but it is general enough to simulate the internals of the 741:

https://www.physicsforums.com/attachment.php?attachmentid=43682&stc=1&d=1328754979
 

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You are probably violating some conditions of the simulation. For example if one of the capacitors has an initial voltage different from the other then this is not a valid circuit and simulation is not possible unless a resistance is inserted as indicated.
 

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