- #1
sweetreason
- 20
- 0
I am trying to solve the problem another poster asked about in
https://www.physicsforums.com/showthread.php?t=382491.
I realize how the problem is supposed to be solved, and that you have to start with the rightmost 3 capacitors because none of the other capacitors are in series or in parallel, but I don't understand why this last fact is the case. Why can't you for instance, find the equivalent capacitor for the two leftmost triples (C1, C2, C1) individually [as these seem to me to each form a self-contained series] and the rightmost (C1, C1, C1) separately, which would leave you with three capacitors in parallel?
Thanks!
https://www.physicsforums.com/showthread.php?t=382491.
I realize how the problem is supposed to be solved, and that you have to start with the rightmost 3 capacitors because none of the other capacitors are in series or in parallel, but I don't understand why this last fact is the case. Why can't you for instance, find the equivalent capacitor for the two leftmost triples (C1, C2, C1) individually [as these seem to me to each form a self-contained series] and the rightmost (C1, C1, C1) separately, which would leave you with three capacitors in parallel?
Thanks!
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