Cardinality of Cartesian Product

AI Thread Summary
The discussion focuses on proving the theory of cardinality for the Cartesian product, specifically that the cardinality of set A is less than or equal to the cardinality of the Cartesian product A × B when B is non-empty. Participants emphasize the importance of defining a one-to-one function to establish this relationship and suggest formalizing the approach for validation. The conversation also touches on the relevance of this proof to understanding the Cantor-Schroder-Bernstein theorem and the use of infinite sequences. Additionally, the Axiom of Choice is mentioned as necessary for certain cardinality arguments. The overall consensus is that a clear definition and formal proof are essential for confirming the logic behind the cardinality relationship.
sujoykroy
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Can you prove the following theory of cardinality for a Cartesian product, -
\left|\:A\:\right|\:\leq\:\left|\:A\:\times\:B\:\right|\: if\: B\neq\phi

In English,
The cardinality of a set A is less than or equal to the cardinality of Cartesian product of A and a non empty set B.
 
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What have you tried? What methods can you use? What ways of restating the problem have you considered?
 
Hi sujoykroy! :smile:

In problems like this, just write out the definition, and then plug the problem into it.

So … what is the definition of "cardinality of P ≤ cardinality of Q"? :smile:

oh … and … what is the definition of "non empty set"? :biggrin:
 
Hurkyl said:
What have you tried? What methods can you use? What ways of restating the problem have you

considered?

I think, if you pick up a binary relation f in such way that f\left(\:a\:\right)\:=\:\left(\:a\:,\:b\:) for some b\:\in\:B for all a\:\in\:A, then f will be a one-to-one function with dom\:f\:=\:A and ran\:f\:\subset\:A\:\times\:B, hence proving that \left|\:A\:\right|\:\leq\:\left|\:A\:\times\:B\:\right|\: if\: B\neq\phi, but i am not sure if the approach is right or not.

tiny-tim said:
Hi sujoykroy! :smile:

In problems like this, just write out the definition, and then plug the problem into it.

So … what is the definition of "cardinality of P ≤ cardinality of Q"? :smile:

oh … and … what is the definition of "non empty set"? :biggrin:

Below is the definition of cardinality that i am using,
The cardinality of a set A is less than or equal to the cardinality of a set B if there is a one-to-one function f on A into B
 
sujoykroy said:
but i am not sure if the approach is right or not.
Well, try formalizing it. If you wind up with a valid proof, then your approach is right. :smile:
 
Hurkyl said:
Well, try formalizing it. If you wind up with a valid proof, then your approach is right. :smile:

Thanks. Actually i was trying to understand/prove the use/existence of Infinite Sequence used in various proof of Cantor-Schroder-Bernstein i.e. if \left|X\right|\:\leq\:\left|Y\right| and \left|Y\right|\:\leq\:\left|X\right| then \left|X\right|\:=\:\left|Y\right| and current problem was a doorway to open up the logical window towards it. So, formalization was not really my problem, i just needed to get confirmation if the logic is correct.
 
sujoykroy said:
Below is the definition of cardinality that i am using,

"The cardinality of a set A is less than or equal to the cardinality of a set B if there is a one-to-one function f on A into B"

Hi sujoykroy! :smile:

Yes, that's the one … so, in this case, you need to define a one-to-one f on A into A x B.

And to do that, answer the question: what is the definition of "non empty set"?

(it may sound a daft question … but sometimes maths is like that! :smile:)
 
I also have a quick query regarding something related to cardinality of a cartesian product.

What does \left|A\right| = \left|A \times \aleph\right|for any set A, tell you about A?

I hope to use this to find an injective function from \aleph^{A}to \left\{0,1\right\}^{A}
 
You need the Axiom of Choice, as far as I can tell. But once you apply the Axiom, it's pretty simple, assuming your definition of A <= B is that there is an injection from A to B (a bijection from A to a subset of B).
 
  • #10
I think you misread the problem.
 
  • #11
Yes, that I did
 
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