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Hi,

We know that a heat engine working on a Carnot Cycle the efficiency is:

1 - Q

But if we use a different absolute temperature scale whose values at T

I am confused about this issue. Where is my reasoning incorrect?

We know that a heat engine working on a Carnot Cycle the efficiency is:

1 - Q

_{L}/Q_{H}= 1 - T_{L}/T_{H}where T is in Kelvin.But if we use a different absolute temperature scale whose values at T

_{H}and T_{L}are different, then the value of efficiency also changes.I am confused about this issue. Where is my reasoning incorrect?

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