(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Question states "The plane that contains the line r=<-2,4,3>+t<3,2-1> and is perpendicular to the plane r=<5,0,0>+s<2,1,0>+t<-1,0,1> is:"

Answer is y+2z=10

2. Relevant equations

Cross product and dot product of vectors

3. The attempt at a solution

I found a vector normal to the plane r=<5,0,0>=s<2,1,0>+t<-1,0,1>

by doing the cross product of the two direction vectors is <2,1,0> x <-1,0,1>

getting <1,-2,1>

than apply rule of n.v=0 ie <1,-2,1> . <x-(-2), y-4, z-3>

to get x+2-2y+8+z-3=0

and so x-2y+z = -7

Not sure what I have done wrong here, could someone explain please?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Cartesian equation of plane that i perpendicular to plane and contains line

**Physics Forums | Science Articles, Homework Help, Discussion**